{"ID":2,"Type":"Status","Key":{"Service":"IDN_RDF"},"State":{"Stream":"Closed","Data":"Suspect","Code":"AlreadyOpen","Text":"Request Rejected: Channel not logged in."}}
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{"ID":2,"Type":"Status","Key":{"Service":"IDN_RDF"},"State":{"Stream":"Closed","Data":"Suspect","Code":"AlreadyOpen","Text":"Request Rejected: Channel not logged in."}}
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Is the reply below satisfactory in resolving your query?
If so please can you click the 'Accept' text next to the appropriate reply. This will guide all community members who have a similar question.
Thanks,
AHS
Hello @james_molohon
Thank you for your participation in the forum. Is the reply below satisfactory in resolving your query?
If so please can you click the 'Accept' text next to the appropriate reply. This will guide all community members who have a similar question.
Thanks,
AHS
@james_molohon
Please be informed that a reply has been verified as correct in answering the question, and has been marked as such.
Thanks,
-AHS
Hi @james_molohon,
You can find more details around the status message within the documentation: https://docs-developers.thomsonreuters.com/1549028126279/14977/#page/Messages%2FStatusMsg.html.
What might be happening is that the server is logging you out. In order for you to maintain an active/live connection is to pay attention to the Ping/Pong protocol used. That is, the server will periodically send you a ping message which will require applications to acknowledge by sending a Pong. The documentation will outline this in more detail.
Hope this resolves your issue.
Hi @james_molohon,
The status indicates that you have not successfully logged in to Websocket Service. Refer to the Quick start (https://developers.thomsonreuters.com/elektron/websocket-api/quick-start?content=34507&type=quick_start) for instructions.
Thanks for your quick response. Is there any additional information available about the Code or Text properties? What possible scenarios would cause this error? I use the same login command and it works most of the time, but recently I'm finding this message in the application logs.