how to get caseIdentifiers method and how to use it ?
For a deeper look into our World Check One API, look into:
1
●0 ●0 ●2
how to get caseIdentifiers method and how to use it in c#
Hello @jignesh,
Thank you for your participation in the forum.
Is the reply below satisfactory in resolving your query? If yes please click the 'Accept' text next to the reply. This will guide all community members who have a similar question. Otherwise please post again offering further insight into your question.
Thanks,
-AHS
Hello @jignesh
Thank you for your participation in the forum.
Is the reply below satisfactory in resolving your query? If yes please click the 'Accept' text next to the reply. This will guide all community members who have a similar question. Otherwise please post again offering further insight into your question.
Thanks,
AHS
Hi,
Please be informed that a reply has been verified as correct in answering the question, and has been marked as such.
Thanks,
AHS
4.2k
●8 ●5 ●6
Hello @jignesh,
"Seq-2a: Check caseID availability" is used to check if a given caseId is available to use when creating or updating a Case. You can achieve this by calling the endpoint "caseIdentifier" using the HEAD method.
After successfully calling this endpoint, if you get the response code 200, you would not be able to use the given case ID as it is already in use within the current user's cases. If you get a 404 response, you can use the case ID to save a case and screen it.
In C#, you have to pass the case ID you are searching for in the URL itself.
For example: https://rms-world-check-one-api-pilot.thomsonreuters.com/v1/caseIdentifiers?caseId=1234
where 1234 is the case ID whose availability you would like to check .
You can refer to the "World-Check One API C# .NET Request Code Examples" uploaded in the "Download" section of the Developer Community to get an understanding of how to send requests to WC1 API using C#. Here is the link:
Kindly let me know if you have further questions on this and I would be glad to help you.
Thanks,
Irfan Khan.
