get list of RICs in chain 0#GRAINS/CASH

Thank you @Alex Putkov. I managed to get the chains of the chain . I wrote your command into a recursive function that keeps digging down the RIC until it reaches the lowest level (code not starting with 0#). Then I calls some more data and append it to a pandas dataframe.

import eikon as ek
import pandas as pd

df_fin = pd.DataFrame(columns = ['Instrument', 'DSPLY_NAME', 'Instrument Description', 'Asset Category Description'])

def get_all_children(parent_ric, dsply_name):
    logger.info(f"Call {parent_ric}")
    df, err = ek.get_data(parent_ric, 'DSPLY_NAME')
    for i, row in df.iterrows():
        if str(row['Instrument']) == parent_ric:
            logger.info(f'Skip {parent_ric} because it returned itself.')
            return
        elif str(row['Instrument']).startswith('0#'):
            # the child is a chain
            logger.info(f"Getting children of {str(row['Instrument'])}" )
            get_all_children(str(row['Instrument']), str(row['DSPLY_NAME']))
        else:
            # the child is an instrument
            logger.info(f"{str(row['Instrument'])} is not a chain so append df" )
            df_child, err_child = ek.get_data( 
                instruments=str(row['Instrument']),
                fields=[
                    'DSPLY_NAME',
                    'TR.InstrumentDescription',
                    'TR.AssetCategory']
            )
            # append to the global variable df_fin
            global df_fin
            df_fin = df_fin.append(df_child)

get_all_children('0#GRAINS/CASH', 'commodity')
df_fin.to_csv('out.csv', index=False)

Hi Shadeun. i just checked my code and we do it in a bit of a lazy fashion. we just go through them, and when we get an error, we wait 10 seconds and then try again (for max 20 times). give that a shot